dayse: (Default)
dayse ([personal profile] dayse) wrote2008-02-27 03:14 am

INSANE

I AM GOING INSANE. TRULY TRULY. JUST CRZY. OMG.

Okay, so normally I'm pretty good with the puzzles/riddles, and I dunno, guys, I DUNNO, maybe it's because it's late and I haven't had enough sleep but I just can't figure this one out and I swear to God I'm just - I'm going to lose it. You are all very smart, SO PLZ - PLZ HALP:

While walking through a market on vacation, you notice a small stand selling cameras. A camera-and-case set is selling for $310. The seller tells you that the camera costs $300 more than the case itself and that the case costs the price of the set minus the cost of the camera.

You decide you'd rather wait on buying a camera and opt to just by the case alone. You hand the seller a $100 bill and see his eyes light up. Think fast now! How much change should you be getting back?


The answer is an actual dollar amount, so it's none of that 'oh they don't take $100 dollar bills' or something like that. And omg, I just know it's going to be something so painfully obvious I'll feel like even more of a dumbass afterwards.

Help me! Help me before I lose my mind [cries]

[hobbles off to bed]
veracity: (Default)

[personal profile] veracity 2008-02-27 08:20 am (UTC)(link)
I would love to help you, truly, but I'm math retarded.

[identity profile] dayse.livejournal.com 2008-02-27 08:22 am (UTC)(link)
The thing is, the math itself isn't the tricky part of the question. It appears to be, but it's not. It almost definitely has something to do with the way the question itself is WORDED, and it's making it seem more complex than it is x_x
veracity: (Default)

[personal profile] veracity 2008-02-27 08:27 am (UTC)(link)
But that's why I'm math retarded. It's the word problem parts.

[identity profile] jcjoeyfreak.livejournal.com 2008-02-27 08:23 am (UTC)(link)
ELEVENTY MILLION!

[identity profile] jcjoeyfreak.livejournal.com 2008-02-27 08:39 am (UTC)(link)
Thanks for replying to me last hor!

[identity profile] dayse.livejournal.com 2008-02-27 08:30 am (UTC)(link)
HOMG.

YIS.

[collapses at your feet]

I knew I'd feel might morphin power stupid after I heard the answer. Thank you x_x

[identity profile] sorchar.livejournal.com 2008-02-27 08:33 am (UTC)(link)
*hugs* Nah. Your brain just wasn't in the right mood for this problem just now, and mine happened to be. God only knows how.

[identity profile] sorchar.livejournal.com 2008-02-27 08:32 am (UTC)(link)
That is, that's how much change you should be getting back.

The price of the case is what everything revolves around, so call it x. The camera costs x+300. The problem is, x+x+300=310, or 2x+300=310. So take away 300 from each side and you get 2x=10, so x=5.

I have no idea how I worked this out. I sucked at math in school.

[identity profile] wenelda.livejournal.com 2008-02-27 08:37 am (UTC)(link)
The seller tells you that the camera costs $300 more than the case itself and that the case costs the price of the set minus the cost of the camera.

so...shouldn't it be 10? which would mean you'd get 90 dollars back?

i hate word problems.

[identity profile] seanarenay.livejournal.com 2008-02-27 08:40 am (UTC)(link)
That is what I thought too, but seriously, math hates me, so idk.

[identity profile] malnpudl.livejournal.com 2008-02-27 09:15 am (UTC)(link)
Huh? How is the answer not $90?

Camera + Case = $310
Camera = $300 + Case
Case = $310 - $300 = $10

$100 bill - $10 (case) = $90 change

Seems very straightforward to me.

[identity profile] c-regalis.livejournal.com 2008-02-27 09:43 am (UTC)(link)
Not quite. The camera is 300 MORE than the case (price for case + 300). And the set is camera plus case [(price for case + 300) <- price for camera ] + [price for case]. So the price for the set is the price for the case plus 300 plus the price for the case. 300 + 2x price for the case. Which is 310.

So, uhm, I am for 95 too. Ahem.

[identity profile] malnpudl.livejournal.com 2008-02-27 06:31 pm (UTC)(link)
Ahhhh... okay. NOW I get it.

This is why you do what you do and I... don't. *g*

[identity profile] liz-w.livejournal.com 2008-02-27 11:41 am (UTC)(link)
If the Camera is $300, and the Case is $10, then the camera would be $290 more than the case, not $300.

[identity profile] likeasunburn.livejournal.com 2008-02-27 11:07 am (UTC)(link)
Another vote for $90 here.

[identity profile] iterationzero.livejournal.com 2008-02-27 11:49 am (UTC)(link)
let x = the cost of the camera
let y = the cost of the case

x + y = 310
x = 300 + y
y = 310 - x

you can substitute the values for x or y from one of the last two equations in to the first one. let's do the x value...

(300 + y) + y = 310
300 + 2y = 310
2y = 10
y = 5

so if he doesn't give you back $95, hit him.

[identity profile] jennytsk.livejournal.com 2008-02-27 02:27 pm (UTC)(link)
I'm of the Camera Case Costs $5, You Get $95 back school.

Camera Case = X
Camera = X + 300

2x + 300 = 310
2x=10
x=5

Camera case costs $5
You get $95 back.

The key phrase is "camera costs $300 more than the case itself", not "camera costs $300"

The camera costs $305.

MATH GEEKS UNITE!
ext_3548: (Default)

[identity profile] shayheyred.livejournal.com 2008-02-27 04:30 pm (UTC)(link)
I'd go to B&H and buy the whole set for $50.

[identity profile] malnpudl.livejournal.com 2008-02-27 09:01 pm (UTC)(link)
You?

WIN.